15x^2-102x-144=0

Solution for 15x^2-102x-144=0 equation:

15x^2-102x-144=0

a = 15; b = -102; c = -144;
Δ = b2-4ac
Δ = -1022-4·15·(-144)
Δ = 19044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19044}=138$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-138}{2*15}=\frac{-36}{30}
=-1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+138}{2*15}=\frac{240}{30}
=8
$